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发表于 2014-6-2 17:03:11
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本帖最后由 meigen 于 2014-10-10 20:19 编辑
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接14楼，单色图的提取稍微麻烦些，他里面只有数据部分而缺少文件头，这个是比较头疼的事情5 A: S7 E h6 h* z+ u+ q
先用ebdump提取出词典文本（本文），然后在里面获取单色图的代码(<1F44>开头，<1F64>结尾)
e4 }+ m4 \! ]4 f2 u# o3 p: ]) U( |3 I) r可以看到4 X# m* N: R# c* a! v2 ?* F
<1F44><0001><w=200,h=256>xxx<1F64>[0001A4BD:0027] r2 D* E; t0 G$ x9 I6 |
这里的w=200,h=256表示图片的尺寸，这个参数后面会用到7 P Q$ I ?- E+ x" u+ R" a
然后<1F64>后面的这一段[0001A4BD:0027]就是单色图数据地址了
/ _% K" {; |5 I4 z先写个Demo 把所有地址都提取出来，顺便排一下序，去掉重复:( T% z4 x2 a$ v+ h# e. j! e
- static void getMonoTag(String f) {
3 G& ^9 f& h5 I - try {
/ T3 ~% B1 M6 ^3 H3 }9 z! }" N - BufferedReader reader = new BufferedReader(new InputStreamReader(new FileInputStream(f+".txt"), "Shift_JIS"));# t2 S. R) ~! d8 o" F& u
- BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(new FileOutputStream(f+".mono.txt"), "UTF-8"));4 M' k+ f/ e% j& t8 E$ i0 [' s
- String line;
$ |- K+ ~$ O% w - ArrayList<String> monos = new ArrayList<String>();2 e" Z4 i2 m5 a9 L- y" n0 K
- while (((line = reader.readLine()) != null)) {
* _; a; t, N# N - while (line.contains("<1F64>")) {. |( I0 |( p0 X% h' Y
- line = line.substring(line.indexOf("<1F64>") + 6); r4 R* G# \( p8 X, t& M7 e& V
- monos.add(line.substring(0, 15));! s& @; f- p% n0 S0 L( h
- }; O& C3 u" z4 o: B5 e; K- P
- }0 i& T* I! O; ]2 k* r
- reader.close();
) `* ?" N- a: L& g: v9 g; L8 j8 O- r - String[] monoa = new String[monos.size()];* }" f5 {. ~, m! \2 _0 w
- monos.toArray(monoa);9 t- C# z8 Q" l/ f* Q) {% Y0 U
- Arrays.sort(monoa);9 j" b4 X2 d+ B* Q
- String last = "";) l7 ~! J" `9 C. u
- for (int i=0; i<monoa.length; i++) {
1 _5 i& a; Z% o5 E6 } - if (!monoa[i].equals(last))# E# b4 r) Q6 o+ @$ q
- writer.write(monoa[i] + "\r\n");
+ c9 _ L5 ?" J; k- k8 t( T - last = monoa[i];% E# H7 C" H: k2 r d2 i
- }
6 n- C- L \: u8 ^/ H6 \ - writer.close();
2 Q6 A2 U0 H( a5 f1 Z - } catch (Exception e) {# V* `# A6 @0 X6 |5 D8 U) t
- e.printStackTrace();
; I( _4 E: ~+ D) ]2 Z - }- w1 d' S/ k+ e' J
- }
6 M. J/ }5 l/ o- k得到了一个.mono.txt的文件
3 |, Y3 e! E2 l: \# Q) {1 ^( k然后开始提取:% Z& {9 W+ B, [9 L: A
上面有提到w=200,h=256这两个参数，不过epwing好像弄反了，200是高，256是宽。 - -
1 S1 `. y9 T( z5 }9 Z, u9 U提取过程中需要手动加上图像的文件头，可自行百度bmp文件格式. P# h D6 u- O- e9 J8 p
- static final int WIDTH = 256;
+ Q) Y$ ~$ |& Y- e( \+ j5 k5 j - static final int HEIGHT = 200;& Z8 w4 p& ^5 U% X V
- static final int WIDTH2 = 32;
" I: ]: _3 b, [. U. `8 T2 U9 X: { - static final int SIZE = WIDTH2 * HEIGHT;, d) C$ S" ~3 q$ p3 H6 r- U5 b% E
- static final int FILE_LEN = SIZE + 62;" U& _+ t. S6 _6 P/ H3 t
- static byte[] filehead = {0x42, 0x4d," i6 U. }( f" y' ^! a: _7 O: Y
- (byte) (FILE_LEN & 0xff), (byte) ((FILE_LEN >> 8) & 0xff), (byte) ((FILE_LEN >> 16) & 0xff), (byte) ((FILE_LEN >> 24) & 0xff),; ]( |/ K9 i Q# |$ }$ a) Y/ _
- 0, 0, 0, 0, 0x3e, 0, 0, 0};) Z. f0 ^* h% E; H0 K
- static byte[] infohead = {0x28, 0, 0, 0,% A/ T$ y' u/ ^+ W/ [
- (byte) (WIDTH & 0xff), (byte) ((WIDTH >> 8) & 0xff), (byte) ((WIDTH >> 16) & 0xff), (byte) ((WIDTH >> 24) & 0xff),' a4 r% @7 U) @: M, A
- (byte) (HEIGHT & 0xff), (byte) ((HEIGHT >> 8) & 0xff), (byte) ((HEIGHT >> 16) & 0xff), (byte) ((HEIGHT >> 24) & 0xff),
8 G4 E) ~, \2 Z- P - 1, 0, 1, 0, 0, 0, 0, 0, T4 f& D- ]& [
- (byte) (SIZE & 0xff), (byte) ((SIZE >> 8) & 0xff), (byte) ((SIZE >> 16) & 0xff), (byte) ((SIZE >> 24) & 0xff),; T/ e- K$ s: r
- 0, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 2, 0, 0, 0, -1, -1, -1, 0, 0, 0, 0, 0};
: l0 G6 J7 w- X) s: y6 b - static void getMonoPic(String f, String m) {
& J/ d' S$ O- p0 i3 ?1 T- M, X - try {
! k! T! h& `9 J9 B# ]( @ - BufferedReader reader = new BufferedReader(new InputStreamReader(new FileInputStream(f+".txt"), "Shift_JIS"));+ e2 L! {5 ]7 u5 o( q0 c
- BufferedReader reader2 = new BufferedReader(new InputStreamReader(new FileInputStream(m+".txt"), "UTF-8"));+ K. ~+ \" ^( ]: o+ A& G4 ]* A [
- OutputStream out = null;' b8 S# c3 f4 Q8 F- `$ c4 S
- String line = "";6 w. A% ]/ W8 e* o6 g( C5 U; s3 U
- String line2 = reader2.readLine();
5 E! @/ s4 i6 R& ^0 D5 ~ - int block = 0;
& T4 K+ R7 t/ c/ M* x Q2 a - int block2 = Integer.parseInt(line2.substring(1, 9), 16);
) p/ n& `6 O4 S8 h5 b5 E - int offs = Integer.parseInt(line2.substring(10, 14), 16);7 n' c: W c* z" ^. u2 u
- byte[] temp = new byte[2048];5 m# Z" B( D# k9 A" O
- byte[] data = new byte[WIDTH2 * HEIGHT];0 A$ _% Y) u6 o
- int[] idxs = new int[WIDTH2 * HEIGHT];
" {' o' S8 g" p+ k% X. z - for (int i=0; i<HEIGHT; i++) {* A) Z* r3 s5 V3 J7 [
- idxs[i * WIDTH2] = (HEIGHT - 1 - i) * WIDTH2;
1 T d$ u8 ~+ Z7 x/ F0 C* r - for (int j=1; j<WIDTH2; j++)
9 |( H- V( ?, T3 |4 [9 b' Q - idxs[i * WIDTH2 + j] = idxs[i * WIDTH2 + j - 1] + 1;! s' M [4 c, X5 y5 v
- }
: ], r# G5 [' B; P: Y" O - int idx = 0;
/ h# X- h. j7 v Y - int didx = 0;
$ D" V+ Q# t7 M" O" P# J - while (((line = reader.readLine()) != null)) { M3 s' h1 a2 n5 S; k& x! [* M' i
- if(line.startsWith("block")) {3 ~/ u9 `- w) C' A8 S) ]
- block = Integer.parseInt(line.substring(6, 11), 16);
9 z v' n8 `' ?* i' x* B4 c - idx = 0;
$ @7 T0 l8 W2 y$ K" K8 ]0 F& u; n: j - }
; z7 r3 Z; d) U2 x4 t - if(line.startsWith("0")) {
" P% F& m0 L4 H& _* O- L& D - for(int i=0; i<16; i++) {
Y( j7 E* K* U9 ^5 W3 u( C- b, o - int a = CHARS.indexOf(line.charAt(5+3*i));
) D' j! u5 s0 J3 R+ u - int b = CHARS.indexOf(line.charAt(6+3*i));, _7 m o9 j2 Z& w( G, y6 l" R
- temp[idx++] = (byte) (a << 4 | b);
" _5 J+ }) f: n) Z - }
; f/ |0 T% o' `0 p$ g% ^ - }1 p, m4 M! R% n2 g
- if (idx == 2048) {
1 r& M8 S$ q( G& V: B - if(block < block2) continue;" X% B" v+ F1 n$ j8 t
- int start = offs;
D" j; O) k( U) S1 n1 r M" u. k - if(didx != 0) start = 0;1 p" P" R! v4 T6 B
- for(int i=0; i<2048; i++) {
% M, C2 P0 Z& w. V' V/ c' q. n8 S - if(i >= start)
: j5 H# S* Y* o2 x2 G E - data[idxs[didx++]] = temp[i];2 y$ S) j* g- b
- if(didx == WIDTH2 * HEIGHT) {
6 R- z5 P# m* k1 [; q - System.out.println(toHex(block2)+"."+toHex(offs));
, r# e3 B& N! b% ?0 o0 b - out = new BufferedOutputStream(new FileOutputStream("pic/"+toHex(block2)+toHex(offs)+".bmp"));
: D* M% E7 S" ` b: o6 X - out.write(filehead);6 r+ W/ }. O1 N* C; q, k2 @
- out.write(infohead);3 d3 s7 |! Y( n! G, J
- out.write(data);& F" I- U6 D! V
- out.flush();
$ ?: X! u% ]" M& A- G# R* L# f - out.close();
/ x" e: Z$ Z* ] - line2 = reader2.readLine();
^! s, B5 w3 J. r9 Q3 s - if(line2 == null || line2.equals("")) {4 A- I& H- R) Q+ v9 }
- reader.close();
# C0 w: E% h" I- N& c7 L - reader2.close();
& S7 [0 G2 V) w( j3 `+ G0 R' p - return;7 H7 Y( C$ I$ }- X; {0 r
- }
9 X% x/ s, S: E4 g. I - block2 = Integer.parseInt(line2.substring(1, 9), 16);
- Z6 b$ ^. m3 Y' L! {1 j - offs = Integer.parseInt(line2.substring(10, 14), 16);& y9 V8 F( j! i% [
- didx = 0;
! A( S- ^ A2 v, e+ Q; S - }
3 z3 |6 F; t- P m1 E; B5 M+ Q! a - }
9 n: Y7 X( y- Q% a4 h2 S - idx = 0;
+ b' b, r" e s0 n - }
. [' Q( a5 I4 \3 _: j9 |3 w& g6 e - }' a j: ]+ p$ ^ Z$ _6 D% B6 j
- reader.close();" I5 {- F A$ ?) H' w
- reader2.close();
' _/ P7 u" n+ ^. d, s - } catch (Exception e) {
& O3 c2 I* ^2 `% ?$ m - e.printStackTrace();5 ^' S$ ]1 D" t
- }+ ~" U; L& ^- B
- }
待编辑...
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回15楼:% k6 N3 j, I& j! r
( }. A1 Z1 W1 I9 s, [代码有一些要改动的地方, 我完善一下就传附件. Z7 K- a# K2 _; l
另外用英文说明这...{:11_336:} + k& g7 u) E' l* k( Y
我先用中文注释一下, 然后再慢慢翻译 |
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楼主
发表于 2013-11-11 10:58:55
